DEFINITION leq_ahead_false_1()
TYPE =
       ∀g:G.∀a1:A.∀a2:A.(leq g (AHead a1 a2) a1)→∀P:Prop.P
BODY =
        assume g: G
        assume a1: A
          we proceed by induction on a1 to prove ∀a2:A.(leq g (AHead a1 a2) a1)→∀P:Prop.P
             case ASort : n:nat n0:nat ⇒
                the thesis becomes ∀a2:A.∀H:(leq g (AHead (ASort n n0) a2) (ASort n n0)).∀P:Prop.P
                    assume a2: A
                    suppose H: leq g (AHead (ASort n n0) a2) (ASort n n0)
                    assume P: Prop
                      suppose H0: leq g (AHead (ASort O n0) a2) (ASort O n0)
                         (H_x) 
                            by (leq_gen_head1 . . . . H0)

                               ex3_2
                                 A
                                 A
                                 λa3:A.λ:A.leq g (ASort O n0) a3
                                 λ:A.λa4:A.leq g a2 a4
                                 λa3:A.λa4:A.eq A (ASort O n0) (AHead a3 a4)
                         end of H_x
                         (H1) consider H_x
                         we proceed by induction on H1 to prove P
                            case ex3_2_intro : x0:A x1:A :leq g (ASort O n0) x0 :leq g a2 x1 H4:eq A (ASort O n0) (AHead x0 x1) ⇒
                               the thesis becomes P
                                  (H5) 
                                     we proceed by induction on H4 to prove <λ:A.Prop> CASE AHead x0 x1 OF ASort  ⇒True | AHead  ⇒False
                                        case refl_equal : ⇒
                                           the thesis becomes <λ:A.Prop> CASE ASort O n0 OF ASort  ⇒True | AHead  ⇒False
                                              consider I
                                              we proved True
<λ:A.Prop> CASE ASort O n0 OF ASort  ⇒True | AHead  ⇒False
<λ:A.Prop> CASE AHead x0 x1 OF ASort  ⇒True | AHead  ⇒False
                                  end of H5
                                  consider H5
                                  we proved <λ:A.Prop> CASE AHead x0 x1 OF ASort  ⇒True | AHead  ⇒False
                                  that is equivalent to False
                                  we proceed by induction on the previous result to prove P
P
                         we proved P
(leq g (AHead (ASort O n0) a2) (ASort O n0))→P
                       assume n1: nat
                          suppose : (leq g (AHead (ASort n1 n0) a2) (ASort n1 n0))→P
                         suppose H0: leq g (AHead (ASort (S n1) n0) a2) (ASort (S n1) n0)
                            (H_x) 
                               by (leq_gen_head1 . . . . H0)

                                  ex3_2
                                    A
                                    A
                                    λa3:A.λ:A.leq g (ASort (S n1) n0) a3
                                    λ:A.λa4:A.leq g a2 a4
                                    λa3:A.λa4:A.eq A (ASort (S n1) n0) (AHead a3 a4)
                            end of H_x
                            (H1) consider H_x
                            we proceed by induction on H1 to prove P
                               case ex3_2_intro : x0:A x1:A :leq g (ASort (S n1) n0) x0 :leq g a2 x1 H4:eq A (ASort (S n1) n0) (AHead x0 x1) ⇒
                                  the thesis becomes P
                                     (H5) 
                                        we proceed by induction on H4 to prove <λ:A.Prop> CASE AHead x0 x1 OF ASort  ⇒True | AHead  ⇒False
                                           case refl_equal : ⇒
                                              the thesis becomes <λ:A.Prop> CASE ASort (S n1) n0 OF ASort  ⇒True | AHead  ⇒False
                                                 consider I
                                                 we proved True
<λ:A.Prop> CASE ASort (S n1) n0 OF ASort  ⇒True | AHead  ⇒False
<λ:A.Prop> CASE AHead x0 x1 OF ASort  ⇒True | AHead  ⇒False
                                     end of H5
                                     consider H5
                                     we proved <λ:A.Prop> CASE AHead x0 x1 OF ASort  ⇒True | AHead  ⇒False
                                     that is equivalent to False
                                     we proceed by induction on the previous result to prove P
P
                            we proved P
∀H0:(leq g (AHead (ASort (S n1) n0) a2) (ASort (S n1) n0)).P
                      by (previous . H)
                      we proved P
∀a2:A.∀H:(leq g (AHead (ASort n n0) a2) (ASort n n0)).∀P:Prop.P
             case AHead : a:A a0:A ⇒
                the thesis becomes ∀a2:A.∀H1:(leq g (AHead (AHead a a0) a2) (AHead a a0)).∀P:Prop.P
                (H) by induction hypothesis we know ∀a2:A.(leq g (AHead a a2) a)→∀P:Prop.P
                () by induction hypothesis we know ∀a2:A.(leq g (AHead a0 a2) a0)→∀P:Prop.P
                    assume a2: A
                    suppose H1: leq g (AHead (AHead a a0) a2) (AHead a a0)
                    assume P: Prop
                      (H_x) 
                         by (leq_gen_head1 . . . . H1)

                            ex3_2
                              A
                              A
                              λa3:A.λ:A.leq g (AHead a a0) a3
                              λ:A.λa4:A.leq g a2 a4
                              λa3:A.λa4:A.eq A (AHead a a0) (AHead a3 a4)
                      end of H_x
                      (H2) consider H_x
                      we proceed by induction on H2 to prove P
                         case ex3_2_intro : x0:A x1:A H3:leq g (AHead a a0) x0 H4:leq g a2 x1 H5:eq A (AHead a a0) (AHead x0 x1) ⇒
                            the thesis becomes P
                               (H6) 
                                  by (f_equal . . . . . H5)
                                  we proved 
                                     eq
                                       A
                                       <λ:A.A> CASE AHead a a0 OF ASort  ⇒a | AHead a3 ⇒a3
                                       <λ:A.A> CASE AHead x0 x1 OF ASort  ⇒a | AHead a3 ⇒a3

                                     eq
                                       A
                                       λe:A.<λ:A.A> CASE e OF ASort  ⇒a | AHead a3 ⇒a3 (AHead a a0)
                                       λe:A.<λ:A.A> CASE e OF ASort  ⇒a | AHead a3 ⇒a3 (AHead x0 x1)
                               end of H6
                               (h1) 
                                  (H7) 
                                     by (f_equal . . . . . H5)
                                     we proved 
                                        eq
                                          A
                                          <λ:A.A> CASE AHead a a0 OF ASort  ⇒a0 | AHead  a3⇒a3
                                          <λ:A.A> CASE AHead x0 x1 OF ASort  ⇒a0 | AHead  a3⇒a3

                                        eq
                                          A
                                          λe:A.<λ:A.A> CASE e OF ASort  ⇒a0 | AHead  a3⇒a3 (AHead a a0)
                                          λe:A.<λ:A.A> CASE e OF ASort  ⇒a0 | AHead  a3⇒a3 (AHead x0 x1)
                                  end of H7
                                  suppose H8: eq A a x0
                                     (H10) 
                                        by (eq_ind_r . . . H3 . H8)
leq g (AHead a a0) a
                                     end of H10
                                     by (H . H10 .)
                                     we proved P
(eq A a x0)→P
                               end of h1
                               (h2) 
                                  consider H6
                                  we proved 
                                     eq
                                       A
                                       <λ:A.A> CASE AHead a a0 OF ASort  ⇒a | AHead a3 ⇒a3
                                       <λ:A.A> CASE AHead x0 x1 OF ASort  ⇒a | AHead a3 ⇒a3
eq A a x0
                               end of h2
                               by (h1 h2)
P
                      we proved P
∀a2:A.∀H1:(leq g (AHead (AHead a a0) a2) (AHead a a0)).∀P:Prop.P
          we proved ∀a2:A.(leq g (AHead a1 a2) a1)→∀P:Prop.P
       we proved ∀g:G.∀a1:A.∀a2:A.(leq g (AHead a1 a2) a1)→∀P:Prop.P